- This topic has 6 replies, 5 voices, and was last updated 5 years ago by
.
-
Posts
-
<p style=”padding-left: 40px;”>Hi folks, hope you’re all doing well.</p>
I was wondering if it were possible to build a pedal that only has the Tight knob of the Friedman BE-OD pedal.Does anyone here know what it does exaclty? It would be cool to have just that knob on a seperate pedal so you can use that with other overdrive pedals. Just thinking how it would need to be designed since it does need input/output, etc.
If anyone has ideas, let me know 🙂
Tom – technically, the “Tight” control of the Best Ever OD is just an adjustable filter that can be applied to any circuit with a similar topology. Have you examined the schematic?
Ah alright. Thanks for the info.
I’ve examined the schematic of Musikding’s The Brown Eye but couldn’t see what it actually does.
So it just rolls off some bass frequencies? In a low shelve way or more of a notch filter or bell curve?
Maybe a simple RC filter? If so, you could design the filter with regard to how much frequency you want to roll off. A simple R-C filter rolls off the frequency response at 6 dB per octave above the cutoff frequency. There a online calculators for figuring out the corner/cutoff frequency.
If you like to do the math yourself, the formula is Frequency = 1/2(Pi)(R)(C) where R is Resistance in Ohms and C is Capacitance in Farads. For example, a TS has a 4K7/0.047uf combination that yields a bass rolloff frequency of 721Hz. Say you want to use 3K3 and 0.33uf, this will drop the value substantially to about 146Hz, letting a lot more bass through. You can figure what you think might suffice using the calculator. Then using SIL sockets do the socket and see method for the R and C values. I found this information on the Learning about Electronics website under calculators years ago. I made a switchable RC filter in a modified OD1 pedal and it works quite well.
Interesting indeed. Thanks for the info.
If you want even more control, add a roto-tone with several value sets.
- You must be logged in to reply to this topic.