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  • December 24, 2023 at 1:07 pm #30514
    Anonymous
    Guest

    Trying to finish my MKC4 with the Ultra-Drive Mod on R15. On the instructions for the DPDT Wiring Board, it says I can use the open row of lugs on the 3PDT can be used for an LED but I’m not sure how to wire the LED into the lugs on the 3PDT. More specifically, I want to use bi-color LED where the green corresponds to the stock value for R15 (47k Ω) and the red corresponds to the Ultra-Drive value for R15 (I’m using 4.7k Ω). Can someone help me with this? Thanks in advance.

    December 24, 2023 at 5:36 pm #30517
    Playsforfun
    Moderator

    Use a common anode bi-color LED. The middle leg of the LED should go to a current limiting resistor and the other end of the resistor to the power source. Each other leg corresponds to a color. Solder the appropriate leg(color) to lugs 1 and 3 of the column of the 3PDT footswitch. The middle lug of that column goes to ground. The current limiting resistor is of your choosing. 1K is super bright. 4K7 no so much. I find a spot in-between. DMM is your friend here.

    December 31, 2023 at 7:15 pm #30553
    Anonymous
    Guest

    Thank you so much! I was using common cathode. Much appreciated…

    January 1, 2024 at 11:12 am #30556
    Billy
    Moderator

    Like this Chris exactly as Playsforfun says in pic form

    You can use a coin cell battery to suss which LED side is red or green + to anode centre pin and ground to outer pins or check the build doc which shows you how to figure out which side is which

     

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